$ q^2 = \left(\frac{158}{3}\right)^2 = \frac{24964}{9} $, so $ 27q^2 = 27 \cdot \frac{24964}{9} = 3 \cdot 24964 = 74892 $

February 22, 2026

$q^2 = \left(\frac{158}{3}\right)^2 = \frac{24964}{9} \), so \( 27q^2 = 27 \cdot \frac{24964}{9} = 3 \cdot 24964 = 74892$

\( q^2 = \left(\frac{158}{3}\right)^2 = \frac{24964}{9} \), so \( 27q^2 = 27 \cdot \frac{24964}{9} = 3 \cdot 24964 = 74892 \)