Since $ 4^{3/2} = (2^2)^{3/2} = 2^3 = 8 $, we have:
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- Question: An astronomer models the orbital period $ T $ of a planet around a star as $ T = k \cdot r^{3/2} $, where $ r $ is the semi-major axis and $ k $ is a constant. If $ T = 8 $ when $ r = 4 $, find $ T $ when $ r = 9 $.
- Solution: First, find the constant $ k $ using the given values:
- = k \cdot 4^{3/2}
- = k \cdot 8 \Rightarrow k = 1
- Thus, the formula becomes $ T = r^{3/2} $.
- Now substitute $ r = 9 $:
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