Time needed to complete $\frac{14}{15}$ at combined rate: $\frac{14/15}{3/20} = \frac{14}{15} \times \frac{20}{3} = \frac{280}{45} = \frac{56}{9} \approx 6.22$ hours

February 22, 2026

$Time needed to complete $\frac{14}{15}$ at combined rate: $\frac{14/15}{3/20} = \frac{14}{15} \times \frac{20}{3} = \frac{280}{45} = \frac{56}{9} \approx 6.22$ hours$

Bob works alone for 1 hour: $\frac{1}{15}$ of the task
Combined work rate when both work: $\frac{1}{12} + \frac{1}{15} = \frac{5+4}{60} = \frac{9}{60} = \frac{3}{20}$
Remaining task after 1 hour: $1 - \frac{1}{15} = \frac{14}{15}$
Total time: $1 + \frac{56}{9} = \frac{65}{9} \approx 7.22$ hours
#### $\frac{65}{9}$ hours (approximately 7.22 hours)
A car travels from City A to City B at an average speed of 60 km/h and returns at 80 km/h. The total travel time is 7 hours. What is the distance between the two cities?

Time needed to complete \(\frac{14}{15}\) at combined rate: \(\frac{14/15}{3/20} = \frac{14}{15} \times \frac{20}{3} = \frac{280}{45} = \frac{56}{9} \approx 6.22\) hours

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